on 8/24/2013 7:44 AM
It turned out that it's not Haskell who was slow in my previous Fibonacci test. It was my lack of Haskell knowledge. Haskell has two integral types - Int, which has bounds -2147483648..2147483647 and Integer, which is unbounded. Both types implement Integral type class, so out fib function can be defined in terms of this type class: OK, now we can test performance of the function parametrizing it with the two concrete types. Integer first: We get our previous result ~15 seconds which is rather slow. Now t[...]
>> Read the full article on vaskir.blogspot.com
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